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Recommended SQL Courses:
SQL Problem Statement:
Ketty gives Eve a task to generate a report containing three columns: Name, Grade and Mark. Ketty doesn't want the NAMES of those students who received a grade lower than 8. The report must be in descending order by grade -- i.e. higher grades are entered first. If there is more than one student with the same grade (8-10) assigned to them, order those particular students by their name alphabetically. Finally, if the grade is lower than 8, use "NULL" as their name and list them by their grades in descending order. If there is more than one student with the same grade (1-7) assigned to them, order those particular students by their marks in ascending order.
Write a query to help Eve.
Input Format:
You are given two tables: Students and Grades. Students contains three columns ID, Name and Marks:
Students |
Grades |
Sample Input:
Sample Output:
Note: Print "NULL" as the name if the grade is less than 8.
- Maria (grade 10)
- Jane (grade 9)
- Julia (grade 9)
- Scarlet (grade 8)
Solution: Using LEFT JOIN & CASE WHEN (MySQL Query):
- CASE WHEN is used to just like IF... Else... in other programming languages.
- LEFT JOIN returns all the records from the left table with records that have matching values in the right table.